---- $R$ is a ([[commutative ring|say, commutative]]) [[ring]]. > [!theorem] Theorem. ([[Poincare duality]]) > Let $M$ be an $R$-[[(homological) orientation of a manifold|oriented]] $d$-[[manifold]]. There is a canonical **duality map** $D=D_{M}: H^{k}_{c}(M;R) \to H_{d-k}(M; R)$ and this map is an [[isomorphism]]. > If $M$ is [[compact]], $H^{k}_{c}(M;R)=H^{k}(M;R)$ and there is a [[The Thom Theorem for oriented manifolds|fundamental class]] $[M]$, then $D_{M}$ is easily defined via the [[cap product]]: $D_{M}([\varphi]):= [M] \frown [\varphi].$ In general, one defines for each [[compact]] [[subspace topology|subspace]] $K \subset M$ a map $D_{M}^{K}: H^{k}(M | K; R) \to H_{d-k}(M ; R)$ as $\mu_{K} \frown -$[^1], then glues these maps into $D$. Details below. ^theorem [^1]: Recall that the (2nd) [[relative cap product]] turns two [[relative singular homology|relative classes]] into an [[singular homology|absolute class]]. > [!proposition] Corollary. > If the $d$-manifold $M$ is moreover [[compact]]: $H^{k}(M; R) \cong H_{d-k}(M;R).$ ^corollary > [!definition] Definition of the duality map $D_{M}$. > We suppress all the '$;Rs from the notation. > > **1.** Recall the definition of [[compactly supported cohomology]] as the [[categorical colimit|colimit]] $H^{k}_{c}(M)= \varinjlim\limits_{K \in \mathcal{K}(M)} H^{k}(M, M-K)= \frac{\coprod_{K \in \mathcal{K}(M)} H^{k}(M, M-K)}{\sim},$ > where the [[equivalence relation]] $\sim$ is given by > > $(K, \alpha) \sim (L, \rho_{KL} \alpha) \text{ for } K \subset L,$ > for $\rho_{KL}:H^{*}(M, M-K) \to H^{*}(M, M- L)$ [[relative singular homology|induced by]] the [[topological pair|map of pairs]] $(M, M-L) \hookrightarrow (M, M-K)$. > > **2.** So a compactly supported cochain $c \in H^{k}_{c}(M)$ is $c=[\alpha_{K}]_{\sim}$ for some $\alpha_{K} \in H^{k}(M, M-K)$. We would like to define $D(c):=D_{M}^{K}(\alpha_{K})=\mu_{K} \frown \alpha_{K},$ > but have to show this is [[well-defined]] independent of who represents the [[equivalence class]] $c$.[^2] > > **3.** It is well-defined indeed, because for all $K \subset L$ compact subsets of $M$, the following [[diagram]] commutes by [[The Thom Theorem for oriented manifolds|uniqueness]] of $\mu_{K}, \mu_{L}$. > > ```tikz > \usepackage{tikz-cd} > \usepackage{amsmath} > \begin{document} > % https://tikzcd.yichuanshen.de/#N4Igdg9gJgpgziAXAbVABwnAlgFyxMJZABgBpiBdUkANwEMAbAVxiRAAkA9AawAoANUgAJ+AWm4BKEAF9S6TLnyEUZAIxVajFmy59BI0QBkps+djwEiq8hvrNWiDgH1gUcdN4BZExphQA5vBEoABmAE4QALZIZCA4EEgATNR22o4AIk6enADSALwAOgWRTE45QkXhEADuYEKiMnIgVdGI1nEJiMma9mzpnIZZhcWlhhUFVbX1INQMdABGMAwACgoWyiBhWP4AFjiNoRGtsfFI7akOIEVhOxAu5UVwTPNwMDhChtIzIHOLK2tKNhbXb7aQUaRAA > \begin{tikzcd} > {H^k(X, X-K)} \arrow[r, "D_M^K=\mu_K \frown -"] \arrow[d, "\rho_{K \subset L}"'] & H_{d-k}(M) \\ > {H^k(X, X-L)} \arrow[ru, "D^L_M=\mu_L \frown -"'] & > \end{tikzcd} > \end{document} > ``` > > [^2]: An equivalent way to phrase this would be that we would like to define the easy map $\coprod_{K \in \mathcal{K}(M)}H^{k}(M, M-K) \to H_{d-k}(M)$ as $(K, \alpha_{K}) \mapsto \mu_{K} \frown \alpha_{K}$, and show this map descends to the quotient $H^{k}_{c}(X)$, which **(3)** verifies is indeed the case. > [!proof]- Proof. ([[Poincare duality]]) > ~ The (well)-definition of $D$ is described above. We need to show now that it is an [[isomorphism]]. - [ ] bring over (i think written notes depart from dexter's, and so those should be used) ---- #### Notation: - [[compactly supported cohomology]] - [[singular cohomology]] - [[singular homology]] ----- #### References > [!backlink] > ```dataview > TABLE rows.file.link as "Further Reading" > FROM [[]] > FLATTEN file.tags as Tag > WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom" > GROUP BY Tag > ``` > [!frontlink] > ```dataview > TABLE rows.file.link as "Further Reading" > FROM outgoing([[]]) > FLATTEN file.tags as Tag > WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom" > GROUP BY Tag > ```