----
Let $k \subset \Omega$ be [[field|fields]], where $\Omega$ is [[algebraically closed]].
> [!definition] Definition. ([[algebraic set]])
> 1. Let $S$ be a subset of $k[T_{1},\dots,T_{n}]$. Put $V(S):= \{ \boldsymbol x \in \Omega^{n}: f(\boldsymbol x)=0 \ \forall f \in S \}$. A set of the form $V(S)$ is called an **(affine)** **$k$-algebraic subset of $\Omega^{n}$**, or an **algebraic subset of $\Omega^{n}$ defined over $k$**.
>
>
>2. Let $X$ be a subset of $\Omega^{n}$. Put $I(X):=\{ f \in k[T_{1},\dots,T_{n}]: f(X)=0 \}.$
A set of the form $I(X)$ is called the **$k$-ideal of $X$**.
>
Clearly, if $\langle S \rangle$ is the [[ideal]] of $k[T_{1},\dots,T_{n}]$ [[ideal generated by a subset|generated by]] $S$, then $V(\langle S \rangle)=V(S)$.
>
By **algebraic subset $V(S)$ of $\Omega^{n}$** (without the $k$- prefix) one means a $\Omega$-algebraic subset of $\Omega^{n}$.
>
>
> ```tikz
> \usepackage{tikz-cd}
> \usepackage{amsmath}
> \definecolor{thistle}{RGB}{216,191,216}
> \usepackage{xcolor}
> \begin{document}
> % https://tikzcd.yichuanshen.de/#N4Igdg9gJgpgziAXAbVABwnAlgFyxMJZABgBpiBdUkANwEMAbAVxiRAGUQBfU9TXfIRQBGclVqMWbANbIAKgH1RAAgA6qqBBxxlisBW68QGbHgJEATGOr1mrRCACSACgAaASkN9Tgy6WHitlIOrl7G-GZCyKIBNpL2IOoA8gC2MADmdAB6hDzeAuYoZLESdmwAas7snlziMFDp8ESgAGYAThApSACs1DgQSAAs1AxYYAmaODj1INQAFjB0UGyQ47OlwYmqcEwARnAwOOsMdLswDAAKEb4OY9iwYe2dSGQg-UiiIAtLKwSsI2MJlppss4mUHOodvtDsdTucrj5CiA7lgHnkQE8uogrG8BohPt9lg5Vv8QKM1g5JiD1kEEpCmGgDkcRnDLtckSi0UZMUgAMx9PHDL6LIngP7HQFsKkzMGbemMmEss5sxFCZFge6sdE8xCvd6IbrajpY-m4pAWWpcIA
> \begin{tikzcd}
> S \arrow[r, "\subset" description, no head, dotted] \arrow[d] & {k[T_1, \dots, T_n]} & \color{thistle}I(X) \arrow[l, "\supset" description, no head, dotted] \\
> \color{thistle}V(S) \arrow[r, "\subset" description, no head, dotted] & \Omega^n & X \arrow[l, "\supset" description, no head, dotted] \arrow[u]
> \end{tikzcd}
> \end{document}
> ```
>
> [!basicproperties]
>
> 1. (Inclusion reversal) For subsets $X \subset Y$ of $\Omega^{n}$, we have $I(X) \supset I(Y)$. Similarly, for subsets $S \subset T$ of $k[T_{1},\dots,T_{n}]$, we have $V(S) \supset V(T)$.
> 2. It follows that $V(I(\cdot))$ and $I(V(\cdot))$ *preserve* inclusions.
> 3. For $S \subset k[T_{1},..,T_{n}]$, we have $S \subset I(V(S))$.
> > [!proof]-
> > $I(V(S))$ is the set of [[polynomial 4|polynomials]] vanishing on the common zeros of elements of $S$. Certainly any $f \in S$ is one of them.
> >
> If $f \in S$ and $\boldsymbol x \in V(S)$, then $f(\boldsymbol x)=0$ by the definition of $V(S)$, and so $f$ vanishes on all of $V(S)$, i.e., $f \in I(V(S))$.
> 3. For $X \subset \Omega^{n}$, we have $X \subset V(I(X))$.
> > [!proof]-
> > $V(I(X))$ is the common vanishing of the set of polynomials vanishing on $X$. Certainly any $\boldsymbol x \in X$ belongs here.
> >
> > Explicitly, if $\boldsymbol x \in X$ and $f \in I(X)$ then $f(\boldsymbol x)=0$ by the definition of $I(X)$, and so $\boldsymbol x$ is a [[root of a polynomial|root]] of all $I(X)$, i.e., $\boldsymbol x \in V(I(X))$.
> 4. In fact, $V(I(X))$ is the smallest $k$-algebraic subset of $\Omega^{n}$ that contains $X$.
> > [!proof]-
> >
> > **(a)** Clearly $V(I(X))$ is $k$-algebraic, and we've just seen it contains $X$.
> > **(b)** Suppose $X \subset Y$ for some $k$-algebraic set $Y \subset \Omega^{n}$. Claim: $V(I(X)) \subset Y$. Indeed, assuming $Y=V(\mathfrak{a})$ for some [[ideal]] $\mathfrak{a}$ of $k[T_{1},\dots,T_{n}]$, one has $V(I(X)) \subset V(I(Y))=V\left( \underbrace{ I\big(V(\mathfrak{a})\big) }_{ \supset \mathfrak{a} } \right) \subset V(\mathfrak{a})=Y.$
> >
>
> 5. In particular, $V(I(X))=X$ if $X (\subset X)$ is $k$-algebraic.
> 6. For every set $X \subset \Omega^{n}$, the [[ideal]] $I(X)$ of $k[T_{1},\dots,T_{n}]$ is [[radical of an ideal|radical]].
> > [!proof]-
> > Always $I(X)\subset \sqrt{ I(X) }$. To see the reverse inclusion, suppose $f \in \sqrt{ I(X) }$, say, $f^{\ell} \in I(X)$ for some $\ell \geq 0$. Then $f^{\ell}(\boldsymbol x)=0$ for all $\boldsymbol x \in X$, and so $f( \boldsymbol x)=0$ since $\Omega$ is an [[integral domain]]. Hence $f \in I(X)$.
>
----
####
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#### References
> [!backlink]
> ```dataview
> TABLE rows.file.link as "Further Reading"
> FROM [[]]
> FLATTEN file.tags as Tag
> WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom"
> GROUP BY Tag
> ```
> [!frontlink]
> ```dataview
> TABLE rows.file.link as "Further Reading"
> FROM outgoing([[]])
> FLATTEN file.tags as Tag
> WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom"
> GROUP BY Tag
> ```