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> [!proposition] Proposition. ([[antimonotone inclusion of Lebesgue spaces wrt a finite measure]])
>
Suppose $(X, \Sigma, \mu)$ is a finite [[measure|measure space]] and $0<p<q<\infty$. Then $\|f\|_{p} \leq \mu(X)^{\frac{1}{p}-\frac{1}{q}} \|f\|_{q}$
for all $f \in \mathcal{L}^{q}(\mu)$. It follows that $\mathcal{L}^{q}(\mu) \subset \mathcal{L}^{p}(\mu)$, and that convergence in $q$-norm implies convergence in $p$-norm.
^proposition
> [!proof]- Proof. ([[antimonotone inclusion of Lebesgue spaces wrt a finite measure]])
> Fix $f \in \mathcal{L}^{q}(\mu)$. Let $r=\frac{q}{p}$, [[dual exponent|so that]] $r'=\frac{q}{q-p}$. Note $r>1$. By [[Hölder's inequality]][^1], $\begin{align}
\int |f|^{p} \, d\mu &\leq \left( \int |f|^{pr} \, d\mu \right)^{1/r}\left( \int |1|^{pr'} \, d\mu \right)^{1/r'} \\
&= \mu(X)^{(q-p)/pq} \left( \int |f|^{q} \, d\mu \right)^{1/r}.
\end{align}$
Now raise both sides of the inequality to the power $\frac{1}{p}$, getting $\left( \int |f|^{p} \, d\mu \right)^{1/p} \leq \mu(X)^{(q-p)/(pq)} \left( \int |f|^{q} \, d\mu \right)^{1/q}$
which is the desired inequality.
[^1]: Namely, [[Hölder's inequality]] with $p$ replaced by $r$ and $f$ replaced by $|f|^{p}$ and $h$ replaced by $1$.
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#### References
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> TABLE rows.file.link as "Further Reading"
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