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> [!theorem] Theorem. ([[continuity preserves compactness]])
> The image of a [[compact]] [[topological space|space]] under a [[continuous]] function is [[compact]].
> [!proof]- Proof. ([[continuity preserves compactness]])
>Let $X$ and $Y$ be [[topological space]]s and $f:X \to Y$ a [[continuous]] map between them, where $X$ is [[compact]]. We will use [[compactness characterization for subspaces]] (note: this result is often employed implicitly), and also that [[preimages and unions commute]] and [[images and unions commute]].
>
Let $\mathscr{A}=\{ A_{\alpha} \}_{\alpha \in J}$ be a [[cover|covering]] of $f(X)$. By [[continuity]], $f^{-1}(\bigcup_{\alpha \in J}^{}A_{\alpha})=\bigcup_{\alpha \in J}^{}f^{-1}(A_{\alpha})$ is an [[cover|open covering]] of $X$. Using compactness, obtain a finite subcover of $X$, $X=\bigcup_{i=1}^{n}f^{-1}(A_{i})$. Then we have $f(\bigcup_{i=1}^{n}f^{-1}(A_{i}))=\bigcup_{i=1}^{n}A_{i} \supset X$
which is a finite subcollection of $\mathscr{A}$ covering $f(X)$. So, $f(X)$ is [[compact]].
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#### References
> [!backlink]
> ```dataview
TABLE rows.file.link as "Further Reading"
FROM [[]]
FLATTEN file.tags
GROUP BY file.tags as Tag
> [!frontlink]
> ```dataview
> TABLE rows.file.link as "Further Reading"
> FROM outgoing([[]])
> FLATTEN file.tags as Tag
> WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom"
> GROUP BY Tag
> ```