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> [!proposition] Proposition. ([[every nonzero ring homomorphism out of a field is injective]])
> Let $\varphi: k \to R$ be a [[ring homomorphism]], where $k$ is a [[field]] and $R$ is a nonzero [[ring]]. Then $\varphi$ is an [[injection]].
^proposition
> [!proof]- Proof. ([[every nonzero ring homomorphism out of a field is injective]])
> Recall [[kernel iff ideal]] and [[division ring iff ideals are {0} and R|commutative ring is a field iff ideals are {0} and R]]. Thus the [[kernel of a ring homomorphism|kernel]] of $\varphi$ is either $\{ 0 \}$ or $k$. But if it is $k$ then the [[first isomorphism theorem for rings]] implies $k / k \cong \{ 0 \}$ is [[ring isomorphism|isomorphic]] to $R$, which can't happen because we assumed $R \neq \{ 0 \}$. Thus $\ker \varphi=\{ 0 \}$ and we are done by [[ring homomorphism is injective iff kernel is trivial iff is a monomorphism]].
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#### References
> [!backlink]
> ```dataview
> TABLE rows.file.link as "Further Reading"
> FROM [[]]
> FLATTEN file.tags as Tag
> WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom"
> GROUP BY Tag
> ```
> [!frontlink]
> ```dataview
> TABLE rows.file.link as "Further Reading"
> FROM outgoing([[]])
> FLATTEN file.tags as Tag
> WHERE Tag = "#definition" OR Tag = "#theorem" OR Tag = "#MOC" OR Tag = "#proposition" OR Tag = "#axiom"
> GROUP BY Tag
> ```