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> [!proposition] Proposition. ([[pseudo-orthogonality of matrix coefficients of nonisomorphic irreps]])
> Let $G$ be a finite [[group]] with complex [[irreducible group representation|irreducible ]] [[group representation|group representations]] $(\rho^{(1)}, V_{1}) \not \cong (\rho^{(2)}, V_{2})$. Fix [[basis|bases]] $\mathfrak{B}_{1}$, $\mathfrak{B}_{2}$ for $V_{1},V_{2}$; let $P(g)$ be the [[matrix]] of $\rho^{(1)}_{g}$ wrt $\mathfrak{B}_{1}$ and $Q(g)$ the [[matrix]] of $\rho^{(2)}_{g}$ wrt $\mathfrak{B}_{2}$. We have the following 'entrywise orthogonality' when averaging over $G$: for all $(i,i')$, $(j,j')$, where $1 \leq i,i' \leq m$ and $1 \leq j,j' \leq n$, $\frac{1}{|G|}\sum_{g \in G}q_{ii'}(g^{-1})p_{j'j}(g)=0.$
^6713a8
> [!proof]- Proof. ([[pseudo-orthogonality of matrix coefficients of nonisomorphic irreps]])
> Let $A=e_{i'j'} \in \mathbb{C}^{m \times n}$ be the [[matrix]] with $1$ in the $i',j'$ entry and $0$ elsewhere. By [[Schur's lemma for groups]], the $G$-[[group-equivariant map|equivariant]] [[matrix]] $\tilde{A}$ formed by [[averaging over a group|averaging]] $A$ over $G$ equals $0$. However, the $(i,j)th$ entry of $\tilde{A}$ is exactly the sum $\frac{1}{|G|}\sum_{g \in G} q_{ii'}(g^{-1})p_{j'j}(g).$
So this sum is zero.
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#### References
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