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> [!proposition] Proposition. ([[straight iff zero curvature]])
> A [[smooth]] [[regular curve]] is straight iff it has zero [[curvature of parameterized curve|curvature]].
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> [!proof]- Proof. ([[straight iff zero curvature]])
> That straight lines have zero curvature is shown in [[curvature of parameterized curve|lines have zero curvature]].
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Conversely, we want to show that given a [[smooth]] [[regular curve]] ([[smooth regular parameterized curves admit (re)parameterizations by arc length|WLOG]] [[parameterization by arc length|parameterized by arc length]]) $\alpha(s), s \in (a,b),$ with the property $\kappa(s) \equiv 0$, that $\alpha$ is a segment of a straight [[line]]. Since $\|\alpha''(s)\|_{2} \equiv 0$, we know by the positive definiteness of [[norm|norms]] that $\alpha''(s) \equiv 0$. Hence $\alpha'(s) \equiv \b c$ for some constant $\b c$, and thus $\alpha(s)= \b c t + \b b$ for some constant $\b b$. This is the result.
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#### References
> [!backlink]
> ```dataview
TABLE rows.file.link as "Further Reading"
FROM [[]]
FLATTEN file.tags
GROUP BY file.tags as Tag
> [!frontlink]
> ```dataview
TABLE rows.file.link as "Further Reading"
FROM outgoing([[]])
FLATTEN file.tags
GROUP BY file.tags as Tag