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> [!proposition] Proposition. ([[the Euler characteristic of an odd-dimensional compact manifold is zero]])
> Let $M$ be an odd-dimensional [[compact]] [[manifold]].[^1] Then the [[the Euler characteristic of an odd-dimensional compact manifold is zero|Euler characteristic]] of $M$ is zero: $\chi(M)=0$.
^proposition
> [!proof]- Proof. ([[the Euler characteristic of an odd-dimensional compact manifold is zero]])
> Say $\text{dim }M=2n+1$.
>
> Pick $R=\mathbb{F}_2$. Then $M$ ([[(homological) orientation of a manifold|like all]] [[manifold|manifolds]]) is $\mathbb{F}_{2}$-oriented. Since we can compute Euler characteristic using coefficients [[field|in]] $\mathbb{F}_2$, have $\chi(M)=\sum_{r=0}^{2n+1}(-1)^{r} \text{dim}_{\mathbb{F}_{2}}H_{i}(M; \mathbb{F}_{2}).$
> But we know $H_{i}(M; \mathbb{F}_{2})\cong_{\text{PD}} H^{2n+1-i}(M; \mathbb{F}_{2}) \cong_{\text{UCT}} \text{Hom}_{\mathbb{F}_{2}\text{-}\mathsf{Mod}}\big(H_{2n+1-i}(M; \mathbb{F}_{2}) , \mathbb{F}_{2}\big)$
> by [[Poincare duality]] and the [[universal coefficients theorem for cohomology|universal coefficients theorem]]. This latter space is in turn isomorphic (via [[dual vector space|dual space]] considerations) to to $H_{2n+1-i}(M; \mathbb{F}_{2})$. So $\text{dim}_{\mathbb{F}_{2}}H_{i}(M; \mathbb{F}_{2})=\text{dim}_{\mathbb{F}_2}H_{2n+1-i}(M; \mathbb{F}_{2}).$
> But these show up in the sum above with opposite signs, so they cancel. The sum is therefore zero.
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[^1]: Technically, with our definitions and results thus far we have to add the assumption '$M$ is [[homotopy equivalent]] to a finite [[cell complex]]'. This is 'not a real requirement'.
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#### References
> [!backlink]
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> [!frontlink]
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